If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2n^2+21n+40=0
a = 2; b = 21; c = +40;
Δ = b2-4ac
Δ = 212-4·2·40
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-11}{2*2}=\frac{-32}{4} =-8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+11}{2*2}=\frac{-10}{4} =-2+1/2 $
| 3n^2-20n+25=0 | | 7k-6k=12 | | 7n+8=-6 | | 2(x+5)+4x-9=2x+7-2(3-x) | | 72+w=3w | | 3(2x+1)=-4(x-2) | | 500/x2-40x=1 | | 22x-8=154 | | 3p+6=62 | | -2z+4z-28=0 | | 8p+12=18 | | x/8-1=0-6 | | 10x-20=4x+2 | | x+(2x+2x)=165 | | 6(x+4)-4(x-7=100 | | 2x+2x=165 | | -8(w+3)=5w+2 | | 7x/6=-14 | | 3u-45=6(u-8) | | 10x+11x=7-4 | | 2x+45-23=67 | | 4w/7=-24 | | 10^x/4=47 | | 5x+4x=7-6 | | 4(3x2)=112 | | 1k/4-2=-4/3 | | 4v-9=65 | | -9x-8+4=28-2x-42 | | 85-2x+x+95+x=180 | | 5/10y=50 | | 19=2m+1.5 | | (3^x+3^x+3^x)/3=3^2 |